Choose current type from drop-down list,input power(P in watts),voltage(in volts) and input the PF and click the Calculate button.

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How to convert electric power in watts (W) to electric current(I) in amps (A)?

### watts to amps calculation formula in case of Direct Current

**I(in Amps) = P(in Watts) / V(in Volts)**

So that you can define “Current are equivalent to the power(in watts) divided by volts(V).

**amps(A) = watt(W) / volt(V)**

**A = W / V**

I=The current I in amps (A)

p=the power P in watts (W)

V=the voltage V in volts (V)

**Let’s take an example**

**Example#1**

Wee need to Find out the current(I) in amps where the power(P) is 300 watts and the voltage(V) supply is 100 volts in the circuit.

I = 300W / 100V = 3A

## How to convert watts to amps?

### watts to amps calculation formula in AC single phase

I= Current in amps (A)

P=the power P in watts (W)

PF=the power factor PF

V=the Root Mean Square voltage V in volts (V)

**I(in Amps) = P(in Watts) / (Power Factor × V(in Volts) )**

So that you can define Current(in amps) are equal to the Power(in watts) divided by PF times volts(V).

**amps(A) = watts(W) / (Power Factor × volts(V))**

or you can re-write formula like this

**A = W / (PF × V)**

**Let’s take an example**

**Example#1**

Find out the current(I) in amps where the power(P) is 300 watts and the PF is 0.8 and the Root Mean Square voltage(V) supply in the circuit is 100 volts

I = 300W / (0.8 × 100V) = 3.75A

###
**watts to amps calculation formula in case of AC three phase line to line voltage**

I=The phase current I in amps (A)

P=the real power P in watts (W)

PF=power factor PF

VL-L=the line to line Root Mean Square voltage VL-L in volts (V)

**I(A) = P(in Watts) / (1.732 × Power Factor × VL-L(in Volts) )**

So that you can define “Current(I) amps are equal to Power(in watts) divided by 1.732 PF times volts”

**amps(A) = watts(W) / (√3 × PF × volts(V))**

or You can re-write this formula like this

**A = W / (√3 × PF × V)**

**Let’s take an example**

**Example#2**

Find out the current(I) in amps where the power(P) is 300 watts, the PF is 0.8 and the Root Mean Square voltage(V) in the circuit is 100 volts.

I = 300W / (1.732 × 0.8 × 100V) =300/138.56=2.165A

### In case of line to neutral voltage

I=The phase current I in amps (A)

P=the real power P in watts (W)

PF=the power factor PF

VL-0=the line to neutral Root Mean Square voltage VL-0 in volts (V)

**I(A) = P(in Watts) / (3 × Power Factor × VL-0(in Volts) )**

So that you can define Cuurent(I) amps are equal to the power(P in watts) divided by 3 times PF times volts(V).

**amps(A) = watts(W) / (3 × PF × volts(V))**

or you can rewrite this formula like this

**A = W / (3 × PF × V)**

**Let’s take an example**

**Example#3**

Find out the current(I) in amps where the power(P) is 300 watts, the PF is 0.8 and the Root Mean Square voltage(V) in the circuit is 100 volts

I = 300W / (3 × 0.8 × 100V) =300W/240=1.25A

where DC = Direct Current, AC = Alternating Current