[Solved]-Functor implementation for types with more than one type-scala

Try

import cats.syntax.functor._

implicit def functor[F[_]: Functor, A]: Functor[Get[F, A, ?]] = new Functor[Get[F, A, ?]] {
  override def map[B, B1](fa: Get[F, A, B])(f: B => B1): Get[F, A, B1] = a => fa.get(a).map(f)
}