[Solved]-Error while creating a UDF in Spark-scala

You get the error because you are returning 1 as an Integer. Also, bigint in hive is actually a Long. So your else is returning Long and your if is returning a Int which makes the return type of your UDF Any which isn't supported by Spark DataFrame. Here's a list of supported datatypes

If you use df.schema, it'll show you that what you actually need is LongType

val df = sqlContext.sql(" select cast(2 as bigint) as a ")
// df: org.apache.spark.sql.DataFrame = [a: bigint]

df.printSchema
// root
//  |-- a: long (nullable = false)


df.schema
// res16: org.apache.spark.sql.types.StructType = StructType(StructField(a,LongType,false))

Your UDF should look something like:

val makeSIfTesla = udf {(make: Long) => if(make == 0) 1.toLong else make}
//makeSIfTesla : UserDefinedFunction = UserDefinedFunction(<function1>,LongType,List(LongType))

However, for something as simple as this, you really don't need a UDF. You can use the when-otherwise construct available in Spark.

df.withColumn("x" , when($"x" === lit(0) , lit(1) ).otherwise($"x") )

where x is the column you are passing to your UDF makeSIfTesla.