Accepted answer

Use Math.max to return the larger of two values. In your case, you want to return the number of days remaining only if that number is greater than 0, otherwise you want to return 0:

const counters =, i) => {
  let untildate =
  let diffDays1=(function(){ 
    let oneDay = 24*60*60*1000 // hours*minutes*seconds*milliseconds
    let secondDate = new Date(untildate);
    let firstDate = new Date();
    return (`${Math.max(0, Math.round(Math.abs((firstDate.getTime() - secondDate.getTime())/(oneDay))))} Days`)


There are many answers for how to get the difference between two dates in days, like this.

Your code seems overly convoluted. Assuming the input dates are in a format like 2019-05-10 and you're using the built-in parser, you can work in UTC and avoid any daylight saving issues.

Just test the difference in days, if it's 0 or less, return zero. Otherwise, return the difference. E.g.

var dates = ['2019-01-01','2019-05-10','2019-05-20'];

var counters = => {
  let diffDays = (new Date(date) - new Date().setUTCHours(0,0,0,0))/8.64e7;
  return diffDays > 0? diffDays : 0;


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