score:2

Accepted answer

A clean and simple way to mock the default export of a module is to use jest.spyOn in combination with functions like mockImplementation.


Here is a working example based on the code snippets above:

config.js

const whatever = async () => 'result';

const configureEnvironment = async (nativeConfig) => await whatever();

export default configureEnvironment;

Scene.js

import * as React from 'react';
import configureEnvironment from './config';

export class Scene extends React.Component {
  constructor(props) {
    super(props);
    configureEnvironment(props.prevState).then((config) => {
      // Do stuff
    });
  }
  render() {
    return null;
  }
}

Scene.test.js

import React, { Fragment } from 'react';
import { shallow } from 'enzyme';

import { Scene } from './Scene';
import * as config from './config';

describe('Scene', () => {

  const mock = jest.spyOn(config, 'default'); // spy on the default export of config
  mock.mockImplementation(() => Promise.resolve('config')); // replace the implementation

  const getScene = (previousState) => {
    return shallow(
      <Scene prevState={previousState}>
        <Fragment />
      </Scene>,
    );
  };

  it('calls configureEnvironment with the nativeConfig', async () => {
    expect.assertions(1);
    const nativeConfig = {};

    getScene(nativeConfig);

    expect(mock).lastCalledWith(nativeConfig);  // SUCCESS
  });
});

score:0

You can mock anything with jest, like this jest.mock('@material-ui/core/withWidth', () => ({ __esModule: true, isWidthUp: jest.fn((a, b) => true), default: jest.fn(fn => fn => fn) }))


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