score:71

Accepted answer

I'm assuming that you are using React-Router V4, as you used the same in the original Sandbox Link.

You are rendering the Main component in the call to ReactDOM.render that renders a Link and Main component is outside of Router, that's why it is throwing the error:

You should not use <Link> outside a <Router>

Changes:

  1. Use any one of these Routers, BrowserRouter/HashRouter etc..., because you are using React-Router V4.

  2. Router can have only one child, so wrap all the routes in a div or Switch.

  3. React-Router V4, doesn't have the concept of nested routes, if you wants to use nested routes then define those routes directly inside that component.


Check this working example with each of these changes.

Parent Component:

const App = () => (
  <BrowserRouter>
    <div className="sans-serif">
      <Route path="/" component={Main} />
      <Route path="/view/:postId" component={Single} />
    </div>
  </BrowserRouter>
);

render(<App />, document.getElementById('root'));

Main component from route

import React from 'react';
import { Link } from 'react-router-dom';

export default () => (
  <div>
    <h1>
      <Link to="/">Redux example</Link>
    </h1>
  </div>
)

Etc.


Also check this answer: Nested routes with react router v4

score:-13

If you don't want to change much, use below code inside onClick()method.

this.props.history.push('/');

score:0

Write router in place of Main in render (last line in the code). Like this ReactDOM.render(router, document.getElementById('root'));

score:0

I base my answer on this article. Here's a simple solution.

// index.test.tsx
import React from "react";
import { render, screen } from "@testing-library/react";
import { Router } from "react-router-dom";
import { createBrowserHistory } from "history";
import Login from ".";

it("should display Login", () => {
  const history = createBrowserHistory();
  render(
    <Router history={history}>
      <Login />
    </Router>
  );
  const linkElement = screen.getByText(/Login/i);
  expect(linkElement).toBeInTheDocument();
});

score:0

Here is my solution, I use react testing library that comes with create-react-app. I know is simpler solution to what you asked, but I was missing the imports in the other answers so I just put it altogether. Here is the test file:

// HomePage.test.js 
import { render, screen } from '@testing-library/react';
import { BrowserRouter } from 'react-router-dom';
import HomePage from './HomePage';

it('Homepage contains heading 1', () => {
  render(
    <BrowserRouter>
      <HomePage />
    </BrowserRouter>
  );

  screen.getByRole('heading', { level: 1 });
});

it('Homepage contains link', () => {
  render(
    <BrowserRouter>
      <HomePage />
    </BrowserRouter>
  );

  expect(screen.getByRole('link')).toHaveAttribute('href', '/articles');
});

The main component that I would be testing would look like this

// HomePage.js
import React from 'react';
import { Link } from 'react-router-dom';

const HomePage = () => {
  return (
    <>
      <h1>Welcome to React page</h1>
      <p>
        Click on <Link to='/articles'>Articles</Link> to see what is shared
        today
      </p>
    </>
  );
};

export default HomePage;

score:1

You can put the Link component inside the Router componet. Something like this:

 <Router>
     <Route path='/complete-profiles' component={Profiles} />
     <Link to='/complete-profiles'>
         <div>Completed Profiles</div>
     </Link>
 </Router>

score:1

Why not try to create another component that just uses the BrowserRouter from "react-router-dom" and wrap your component with the Link inside it.

const ReduxExample () => (
  <div>
    <h1>
      <Link to="/">Redux example</Link>
    </h1>
  </div>
)

then you can do this

const NewReduxExample = () => {
   <BrowserRouter>
     <ReduxExample />
   </BrowserRouter>
};

score:1

Alternatively, you can do this in your index.js file in your src folder.

import React from 'react'; import ReactDOM from 'react-dom'; import { BrowserRouter as Router } from 'react-router-dom';

import App from './App';

ReactDOM.render(<Router><App /></Router>, document.getElementById('root'));

Then in your Component.jsx file you can import Link

import { Link } from 'react-router-dom';

and use the Link like so without a Router/Route tag.

<Link to="/">Page</Link>

score:1

wrap every component inside BrowserRouter where you're calling reactDom.render like this

import {BrowserRouter} from 'react-router-dom'

ReactDOM.render(

  <React.StrictMode>
    <BrowserRouter>
    <App />
    </BrowserRouter>
  </React.StrictMode>,
  document.getElementById('root')
);

score:2

add this to your index.js:

import { BrowserRouter as Router } from "react-router-dom"; 

and then wrap your <App /> within the <Router></Router> to use links within your react application.

like this:

import React from "react";
import ReactDOM from "react-dom";
import { BrowserRouter as Router } from "react-router-dom";

import App from "./App";

ReactDOM.render(
    <Router>
        <App/>
    </Router>, 
    document.getElementById('root'));

score:3

I kinda come up with this code :

import React from 'react';
import { render } from 'react-dom';

// import componentns
import Main from './components/Main';
import PhotoGrid from './components/PhotoGrid';
import Single from './components/Single';

// import react router
import { Router, Route, IndexRoute, BrowserRouter, browserHistory} from 'react-router-dom'

class MainComponent extends React.Component {
  render() {
    return (
      <div>
        <BrowserRouter history={browserHistory}>
          <Route path="/" component={Main} >
            <IndexRoute component={PhotoGrid}></IndexRoute>
            <Route path="/view/:postId" component={Single}></Route>
          </Route>
        </BrowserRouter>
      </div>
    );
  }
}

render(<MainComponent />, document.getElementById('root'));

I think the error was because you were rendering the Main component, and the Main component didn't know anything about Router, so you have to render its father component.

score:4

I was getting this error because I was importing a reusable component from an npm library and the versions of react-router-dom did not match.

So make sure you use the same version in both places!

score:5

Make it simple:

render(<BrowserRouter><Main /></BrowserRouter>, document.getElementById('root'));

and don't forget: import { BrowserRouter } from "react-router-dom";

score:16

Whenever you try to show a Link on a page thats outside the BrowserRouter you will get that error.

This error message is essentially saying that any component that is not a child of our <Router> cannot contain any React Router related components.

You need to migrate your component hierarchy to how you see it in the first answer above. For anyone else reviewing this post who may need to look at more examples.

Let's say you have a Header.jscomponent that looks like this:

import React from 'react';
import { Link } from 'react-router-dom';

const Header = () => {
    return (
        <div className="ui secondary pointing menu">
            <Link to="/" className="item">
                Streamy
            </Link>
            <div className="right menu">
                <Link to="/" className="item">
                    All Streams
                </Link>
            </div>
        </div>
    );
};

export default Header;

And your App.js file looks like this:

import React from 'react';
import { BrowserRouter, Route, Link } from 'react-router-dom';
import StreamCreate from './streams/StreamCreate';
import StreamEdit from './streams/StreamEdit';
import StreamDelete from './streams/StreamDelete';
import StreamList from './streams/StreamList';
import StreamShow from './streams/StreamShow';
import Header from './Header';

const App = () => {
  return (
    <div className="ui container">
      <Header />
      <BrowserRouter>
        <div>
        <Route path="/" exact component={StreamList} />
        <Route path="/streams/new" exact component={StreamCreate} />
        <Route path="/streams/edit" exact component={StreamEdit} />
        <Route path="/streams/delete" exact component={StreamDelete} />
        <Route path="/streams/show" exact component={StreamShow} />
        </div> 
      </BrowserRouter>
    </div>
  );
};

export default App;

Notice that the Header.js component is making use of the Link tag from react-router-dom but the componet was placed outside the <BrowserRouter>, this will lead to the same error as the one experience by the OP. In this case, you can make the correction in one move:

import React from 'react';
import { BrowserRouter, Route } from 'react-router-dom';
import StreamCreate from './streams/StreamCreate';
import StreamEdit from './streams/StreamEdit';
import StreamDelete from './streams/StreamDelete';
import StreamList from './streams/StreamList';
import StreamShow from './streams/StreamShow';
import Header from './Header';

const App = () => {
  return (
    <div className="ui container">
      <BrowserRouter>
        <div>
        <Header />
        <Route path="/" exact component={StreamList} />
        <Route path="/streams/new" exact component={StreamCreate} />
        <Route path="/streams/edit" exact component={StreamEdit} />
        <Route path="/streams/delete" exact component={StreamDelete} />
        <Route path="/streams/show" exact component={StreamShow} />
        </div> 
      </BrowserRouter>
    </div>
  );
};

export default App;

Please review carefully and ensure you have the <Header /> or whatever your component may be inside of not only the <BrowserRouter> but also inside of the <div>, otherwise you will also get the error that a Router may only have one child which is referring to the <div> which is the child of <BrowserRouter>. Everything else such as Route and components must go within it in the hierarchy.

So now the <Header /> is a child of the <BrowserRouter> within the <div> tags and it can successfully make use of the Link element.

score:21

Enclose Link component inside BrowserRouter component

 export default () => (
  <div>
   <h1>
      <BrowserRouter>
        <Link to="/">Redux example</Link>
      </BrowserRouter>
    </h1>
  </div>
)

score:139

For JEST users

if you use Jest for testing and this error happen just wrap your component with <BrowserRouter>

describe('Test suits for MyComponentWithLink', () => {
it('should match with snapshot', () => {
const tree = renderer
  .create(
    <BrowserRouter>
      <MyComponentWithLink/>
    </BrowserRouter>
  )
  .toJSON();
 expect(tree).toMatchSnapshot();
 });
});

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