score:0
var list = db.lands.where(lnd => lnd.owners.any(x => x.name.contains("smit")));
score:0
var lands = db.owners.where(o => o.name.contains("smit")).select(o => o.lands);
score:2
var list = db.lands.join(db.owners.where(x=> x.name.contains("smit")), a=> a.id, b => b.landid, (a,b) => a).tolist();
Source: stackoverflow.com
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