score:2
Accepted answer
You can return distinct values of the Platform collection by using Enumerable.Distinct().
The Platforms value in the result selector in your .GroupBy() operation should be computed as follows:
Platforms = g.Select(p => p.Platform).Distinct().ToList()
score:0
Maybe you could try something like this:
var group = recordList.GroupBy(r => r.Article)
.Select(a =>
new
{
Article = a.Key,
Platforms = a.GroupBy(g => g.Platform)
});
Source: stackoverflow.com
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