score:0
this will do the trick:
iqueryable<animal> query =
from animal in context.animals
where animal.animalaliases
.any(a => a.alias.contains("userinput"))
select animal;
alternatively, you can do it the other way around (start at the animalalias
entity instead of starting at the animal
entity):
iqueryable<animal> query = (
from animalalias in context.animalaliases
where animalalias.alias.contains("userinput")
select animalalias.animal)
.distinct();
score:3
i think what you're looking for is just a normal where clause?
var query = from animal in context.animals
join animalalias in context.animalaliases on animal.animalid equals animalalias.animalid
where animalalias.alias.contains(userinput)
select animal;
the alias text is not part of the foreign key relationship - so it shouldn't be in the join.
update - after comments - including from @steven - while the query above is correct and does mimic the original sql - it might be wise to use distinct()
on the output - this will prevent the case where multiple alias matches could occur for a single animal.
var query = (from animal in context.animals
join animalalias in context.animalaliases on animal.animalid equals animalalias.animalid
where animalalias.alias.contains(userinput)
select animal).distinct();
Source: stackoverflow.com
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