score:8

Accepted answer 
(from pro in Products.ToList()
let max = Max(pro.DateSend, pro.DateEdit)
select max).Max()


static DateTime? Max(DateTime? a, DateTime? b)
{
    if (!a.HasValue && !b.HasValue) return a;  // doesn't matter

    if (!a.HasValue) return b;  
    if (!b.HasValue) return a;

    return a.Value > b.Value ? a : b;
}

score:1 

((from pro in Products.ToList()
select pro.DateSend).Union(
from pro2 in Products.ToList()
select pro.DateEdit
)).Max();

score:7

If you're not opposed to ditching the query syntax it's simpler to do:

DateTime max = Products.Max(p=>p.DateSend > p.DateEdit ? p.DateSend : p.DateEdit);

score:0

Same code but with One LinQ

   (From pro in Products.ToList
    Let max = {pro.DateSend, pro.DateEdit}.Max
    select max).Max

If pro items not a valid DateTime, It will crash or return unexpected result.

Other solution(Parsing the Products list items):

 (From pro in Products.ToList
    Let DSend as DateTime = Convert.ToDateTime(Iif(ValidDateTime(pro.DateSend), pro.DateSend, DateTime.MinValue))
    Let DEdit as DateTime = Convert.ToDateTime(Iif(ValidDateTime(pro.DateEdit), pro.DateEdit, DateTime.MinValue))
    Let MaxDate as DateTime= {DSend, DEdit}.Max
    select MaxDate).Max

private function ValidDateTime(ByVal Dat as Object) as Boolean
   if Dat Is Nothing OrElse IsDbNull(Dat) OrElse String.IsNullOrEmpty(Dat)  then
      return false
   end if

   return true
end function

You can replace the ValidDateTime with an "Iif".

Other example returning max value of Double items, but in the personalized object(MyObject), items are String type.

  (From Item as MyObject in MyListOfObject
    Let Frec as Double = Convert.ToDouble(Iif(String.IsNullOrEmpty(Item.Frecuency),0,Item.Frecuency))
    Let Pot as Double = Convert.ToDouble(Iif(String.IsNullOrEmpty(Item.Power),0,Item.Power))
    Let max as Double= {Frec, Pot}.Max
    select max).Max

Recap

  1. Declare Column Items separately. Parse It(If you need)
  2. Create an Item for store the max value of the row(all columns)
  3. Create an Array, put in all declared Items and asign array to the before declared item(Item created in step 2)
  4. Append in the end of the array the Max property like this: {Item1, Item2,...}.Max
  5. Create Select fr return the Max item
  6. Append in the end the linq Max property. (MyLinQ).Max

I hope this code helps to someone. Sorry for my English.


Related Articles