score:15
Accepted answer
var distinctitems = mylist.groupby(x => x.prop1).select(y => y.first());
score:1
you can also use morelinq distinctby:
distinctitems = mylist.distinctby(x => x.prop1).tolist();
or with several properties:
distinctitems = mylist.distinctby(x=> new { x.prop1, x.prop2}).tolist();
Source: stackoverflow.com
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