score:1
To select all properties of property l just select it whole:
return expression.InnerJoin(
DbExpressionBuilder.Scan(joinEntity),
(l, r) => DbExpressionBuilder.Equal(
DbExpressionBuilder.Property(l, "JoinId"),
DbExpressionBuilder.Property(r, "JoinId")
)
)
.Select(exp => exp.Property("l"));
This will automatically generate query selecting all columns that "l" has.
Source: stackoverflow.com
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