## How to convert apparent power in kilovolt-amps (kVA) to electric current in amps (A)?

### kVA to amps calculation formula in case of Single phase

I=The phase current I in amps

S=the apparent power S in kilovolt-amps

V=the Root Mean Square voltage V in volts

**I(A) = 1000 × S(in kVA) / V(in Volts)**

So that you can define Cuurent(I) in amps are equal to 1000 times KVA divided by Voltage(V).

**amps(A) = 1000 × kVA / volts(V)**

**or you can re-write this formula like that**

**A = 1000 x kVA / V**

**Let’s take an example**

**Example#1**

We need to find out the current(I) in amps of an electric circuit where power(S) is 5 kVA and root mean square voltage in the circuit is 100 volts

Apply formula for the Solution:

I = 1000 × 5kVA / 100V = 50A

### kVA to amps calculation formula in case of 3 phase with line to line voltage

I=The phase current I in amps

S= the apparent power S in kilovolt-amps

VL-L= the line to line Root Mean Square voltage V in volts

**I(A) = 1000 × S(in kVA) / (1.732 × VL-L(in Volts) )**

So that you can define cuurent(I) in amps are equal to 1000 times KVa divided by the 1.732 times volts(V).

**amps = 1000 × kVA / (1.732 × volts)**

**Let’s take an example**

**Example#2**

We need to find out the current(I) in amps of an electric circuit where the power(S) is 5 kVA and the line to line root mean square voltage supply is 150 volts in the circuit.

Apply formula for the Solution:

I = 1000 × 5kVA / (1.732 × 150V) = 19.236A

### kVA to amps calculation formula in case of 3 phase with line to neutral voltage

I=The phase current I in amps

S=the apparent power S in kilovolt-amps

VL-Nthe line to line RMS voltage V in volts

**I(A) = 1000 × S(in kVA) / (3 × VL-N(in Volts) )**

So that you can define Current(I) in amps are equal to 1000 times Power in KVA divided by 3 times voltage.

**amps(A) = 1000 × kVA / (3 × volts(V))**

**or**

**A = 1000 x kVA / (3 × V)**

**Let’s take an example**

**Example#3**

We need to find out the current(I) in amps of an electric circuit where the power(S) is 5 kVA and the line to neutral root mean square voltage supply is 150 volts in the circuit.

Apply formula for the Solution:

I = 1000 × 5kVA / (3*150V) = 1.11A

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