score:2
If you have a local variable it makes no sense using an asynchronous call to pass it. Just pass it straight away as an argument:
var sampleData = [...];//this is your data
makeGraphs(sampleData);//call your function using it as an argument
And then:
function makeGraphs(data){//this is the parameter
//use 'data' here
}
Source: stackoverflow.com
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