score:66

Accepted answer

You should create a separate array for colors ( just like the ict_unit and efficiency ), instead of assigning a random color value each time to the coloR variable.

Here is the revised version of your code :

$(document).ready(function() {
   $.ajax({
      url: "https://jsonblob.com/api/jsonBlob/a7176bce-84e0-11e7-8b99-016f34757045",
      method: "GET",
      success: function(data) {
         console.log(data);
         var ict_unit = [];
         var efficiency = [];
         var coloR = [];

         var dynamicColors = function() {
            var r = Math.floor(Math.random() * 255);
            var g = Math.floor(Math.random() * 255);
            var b = Math.floor(Math.random() * 255);
            return "rgb(" + r + "," + g + "," + b + ")";
         };

         for (var i in data) {
            ict_unit.push("ICT Unit " + data[i].ict_unit);
            efficiency.push(data[i].efficiency);
            coloR.push(dynamicColors());
         }
         var chartData = {

            labels: ict_unit,
            datasets: [{
               label: 'Efficiency ',
               //strokeColor:backGround,

               backgroundColor: coloR,

               borderColor: 'rgba(200, 200, 200, 0.75)',
               //hoverBackgroundColor: 'rgba(200, 200, 200, 1)',
               hoverBorderColor: 'rgba(200, 200, 200, 1)',
               data: efficiency
            }]
         };

         var ctx = $("#my-canvas");
         var barGraph = new Chart(ctx, {
            type: 'pie',
            data: chartData
         })
      },
      error: function(data) {

         console.log(data);
      },
   });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.6.0/Chart.min.js"></script>
<canvas id="my-canvas"></canvas>

score:1

An example snippet for rgb color picker between 235 and 52

const randomNum = () => Math.floor(Math.random() * (235 - 52 + 1) + 52);

const randomRGB = () => `rgb(${randomNum()}, ${randomNum()}, ${randomNum()})`;

console.log(randomRGB());

Resource:


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