# Online Watts to amps calculator

Use this online  converter for converting Electric power(P in watts) to electric current(I) in amps (A) calculator.
Choose current type from drop-down list,input power(P in watts),voltage(in volts) and input the PF and click the Calculate button.

 current type: DC AC - Single phase AC - Three phase power in watts: W Select voltage type: Line to line voltage Line to neutral voltage voltage in volts: V Enter power factor: Current result in amps: A

## How to convert electric power in watts (W) to electric current(I) in amps (A)?

### watts to amps calculation formula in case of Direct Current

I(in Amps) = P(in Watts) / V(in Volts)
So that you can define "Current are equivalent to the power(in watts) divided by volts(V).
amps(A) = watt(W) / volt(V)
or
A = W / V
I=The current I in amps (A)
p=the power P in watts (W)
V=the voltage V in volts (V)
Let's take an example
Example#1
Wee need to Find out the current(I) in amps where the power(P) is 300 watts and the voltage(V) supply is 100 volts in the circuit.
I = 300W / 100V = 3A

## How to convert watts to amps?

### watts to amps calculation formula in AC single phase

I= Current in amps (A)
P=the power P in watts (W)
PF=the power factor PF
V=the Root Mean Square voltage V in volts (V)
I(in Amps) = P(in Watts) / (Power Factor × V(in Volts) )
So that you can define Current(in amps) are equal to the Power(in watts) divided by PF times volts(V).
amps(A) = watts(W) / (Power Factor × volts(V))
or you can re-write formula like this
A = W / (PF × V)
Let's take an example
Example#1
Find out the current(I) in amps where  the power(P) is 300 watts and the PF is 0.8 and the Root Mean Square voltage(V) supply in the circuit is 100 volts
I = 300W / (0.8 × 100V) = 3.75A

### watts to amps calculation formula in case of AC three phase line to line voltage

I=The phase current I in amps (A)
P=the real power P in watts (W)
PF=power factor PF
VL-L=the line to line Root Mean Square voltage VL-L in volts (V)
I(A) = P(in Watts) / (1.732 × Power Factor × VL-L(in Volts) )
So that you can define "Current(I) amps are equal to Power(in watts) divided by 1.732 PF times volts"
amps(A) = watts(W) / (√3 × PF × volts(V))
or You can re-write this formula like this
A = W / (√3 × PF × V)
Let's take an example
Example#2
Find out the current(I) in amps where the power(P) is 300 watts, the PF is 0.8 and the Root Mean Square voltage(V) in the circuit is 100 volts.
I = 300W / (1.732 × 0.8 × 100V) =300/138.56=2.165A

### In case of line to neutral voltage

I=The phase current I in amps (A)
P=the real power P in watts (W)
PF=the power factor PF
VL-0=the line to neutral Root Mean Square voltage VL-0 in volts (V)
I(A) = P(in Watts) / (3 × Power Factor × VL-0(in Volts) )
So that you can define Cuurent(I) amps are equal to the power(P in watts) divided by 3 times PF times volts(V).
amps(A) = watts(W) / (3 × PF × volts(V))
or you can rewrite this formula like this
A = W / (3 × PF × V)
Let's take an example
Example#3
Find out the current(I) in amps where the power(P) is 300 watts, the PF is 0.8 and the Root Mean Square voltage(V) in the circuit is 100 volts
I = 300W / (3 × 0.8 × 100V) =300W/240=1.25A
where DC = Direct Current, AC = Alternating Current